Difference between revisions of "Translations:Swap/20/en"

Latest revision as of 18:48, 7 September 2021

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For more modern systems (>4GB), your swap space should be at a minimum be ROUNDUP(SQRT(RAM)) I.E. the square root of your RAM size rounded up to the next GB. '''However, if you use hibernation''', you need a minimum of physical memory (RAM) size '''plus''' ROUNDUP(SQRT(RAM)). The maximum, is again twice the amount of RAM, again because of diminishing returns.

For more modern systems (>4GB), your swap space should be at a minimum be ROUNDUP(SQRT(RAM)) I.E. the square root of your RAM size rounded up to the next GB.  '''However, if you use hibernation''', you need a minimum of physical memory (RAM) size '''plus''' ROUNDUP(SQRT(RAM)). The maximum, is again twice the amount of RAM, again because of diminishing returns.

For more modern systems (>4GB), your swap space should be at a minimum be ROUNDUP(SQRT(RAM)) I.E. the square root of your RAM size rounded up to the next GB. However, if you use hibernation, you need a minimum of physical memory (RAM) size plus ROUNDUP(SQRT(RAM)). The maximum, is again twice the amount of RAM, again because of diminishing returns.

Revision as of 11:12, 31 March 2021 (view source) FuzzyBot (talk \| contribs) (Importing a new version from external source)		Latest revision as of 18:48, 7 September 2021 (view source) FuzzyBot (talk \| contribs) (Importing a new version from external source)
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	For more modern systems (>4GB), your swap space should be at a minimum be ~~equal to your physical memory~~ (RAM) size '''if you use hibernation''', ~~otherwise~~ you need a minimum of ROUNDUP(SQRT(RAM)) ~~I.E. the square root of your RAM size rounded up to the next GB~~. The maximum, is again twice the amount of RAM, again because of diminishing returns.		For more modern systems (>4GB), your swap space should be at a minimum be ROUNDUP(SQRT(RAM)) I.E. the square root of your RAM size rounded up to the next GB. '''However, if you use hibernation''', you need a minimum of physical memory (RAM) size '''plus''' ROUNDUP(SQRT(RAM)). The maximum, is again twice the amount of RAM, again because of diminishing returns.